hi all i’m new here so a warm hello to you all,ive been working with systems for ages,just testing small stakes and often wondered what would happen if two computers were running on the same table ,betting on opposite sides of the 50/50 bets with a progressive stake kicking in on the losing bet after each spin.please dont shoot the newbie for being totally stupid.any thoughts

You should continue. Soon you will find the answer. Also, share your data with all, here. It took Albert Einstein over 8 years to perfect the law of relativity. A law that was impossible to others. Continue, and you will see for your self…

Zero?

If im understanding u correct.

computer A cover 50% of the wheel

computer B cover the other 50% of the wheel???

There is no difference whatsoever if u did this on 1 wheel!

If u bet on 50% on one wheel, and if that loses, bet on 50% of the other wheel with an increse, u could just do the 50% with an increase on the same wheel.

I know what youre thinkin, i had the same thought ages ago lol

Covering the entire wheel will only cost you money or at best will give a breakeven. What you loose with one computer you will gain with the other. But the 0 will take the money from both your computers so the Casino will receive the house edge. This the the nature of roulette. If you cover all numbers including the 0 then you will loose one unit evry spin. ( the same house edge percentage)
as you will need to bet 37 numbers and you get 1 bet back plus 35 profit. So you bet 37 and you get 36 back. 

Throwing your money is a faster way if you want to throw your money away…...

Cheers
CO

.

Trust me, you will be wasting your money.

Think about this.
Computer A plays 30 numbers (say 1-30)
Computer B plays 30 numbers (say 0 and 8-36)
When number 8-30 comes bot A and B win and both will win 6 units so together you win 12 units (so this is on 23 numbers)
On the reamining 14 numbers you will loose: When one of these numbers come up than A will loose 30 units and B will win 6 units so these numbers give a loss of 24.
So this menas : 23 numbers win of 12 = 276 units profit
                14 numbers loss of 24 = 336 units loss
In the long run all numbers will come an equal time so you are losing money all the time. 

Please believe me there is NO COMBINATION possible with roulette which will voercome the house edge.
And if you play on a tabel without zero you will break even in the long run. In that case the above maths will look as follows:

24 numbers will give a win of 12
12 numbers will give a loss of 24
A child can understand that this results in a break even… which is wasting your time.

Cheers
CO