Hello all, I’m new to the forums and to roulette in general. I got started using the martingale strategy in European roulette, which of course doesn’t work in the long run but I figured I should get out of a game while on a winning streak. Anyways I was wondering if placing multiple bets on the outside would give the player better odds? For instance, placing 50 cents on red and 50 cents on even as opposed to a dollar on red. Would your odds be better since those are two separate events even though the odds of each individually are the same? What kills players using the martingale strategy is the table limit and hitting the same color multiple times in a row. So what are the odds of it being the same color (red/black) AND being the same parity (even/odd) for let’s say 10 times in a row?

lasagna - 15 January 2016 05:33 AM

Hello all, I’m new to the forums and to roulette in general. I got started using the martingale strategy in European roulette, which of course doesn’t work in the long run but I figured I should get out of a game while on a winning streak. Anyways I was wondering if placing multiple bets on the outside would give the player better odds? For instance, placing 50 cents on red and 50 cents on even as opposed to a dollar on red. Would your odds be better since those are two separate events even though the odds of each individually are the same? What kills players using the martingale strategy is the table limit and hitting the same color multiple times in a row. So what are the odds of it being the same color (red/black) AND being the same parity (even/odd) for let’s say 10 times in a row?

  Hi Lasagna, welcome to the forum. At one time I played all 3 outside EC bets. R/B,H/L and O/E. Not always at the same time !   ! waited for one of the EC’s to win 3 times then bet on the opposite. Martingale 1-2-3, 3 steps only. Most of the time this will show a small profit.

    If you want a surer profit. If you lose 3 bets. wait for the current streak to end. Then USE THE FOLLOWING RECOVERY TECHNIQUE !

    3…...3
    4…...4
    5…...5
    6…...6
    7…...7
    8…...8
    9…...9
    10….10   etc.

  YOU CAN HANDLE A 20 SPIN DEVIATION WITH 100 UNITS. AND CLEAR THE LINE WITH 10 WINS. THE TRICK IS NEVER REDUCE YOUR BET UNTIL THE LOSS LINE IS CLEAR. 

    eg.  Blk wins 3x . you bet red.You lose the 3 martingale bets. Wait for the streak to end. Bet 3 units on red. lose. bet 3 units on red. lose you are now minus 12 units bet 4 units on red. win -8. bet 4unitts on red. win -4. bet 4 units on red win, line clear. re-start on new target with 3 step marty.

    .YOU HAVE LOST 5 BETS AND WON 3

      Harry

lasagna - 15 January 2016 05:33 AM

So what are the odds of it being the same color (red/black) AND being the same parity (even/odd) for let’s say 10 times in a row?

My main game is craps, so I may be wrong when I say that regardless of which two EC bets you choose to make (providing they are not exact opposites of course) you are not betting on 10 numbers out of the 37 available.  Hence the probability of losing both bets some number of times (call it N) is (10/37)^N.  For N=10 (i.e. ten consecutive losses of both bets) that comes out to be 0.00000208.

I do not think that is the probability you want, however, because you do not necessarily win all of the other spins; on most of them you will win one bet and lose one bet to break even.  What I think you are actually looking for is the probability you will lose ten times before you win once.  If my assumption that two EC bets have 9 common numbers, then their opposites would have 10 numbers.  We can ignore the break-even spins, so your probability of losing ten times before winning once is (10/19)^10, or 0.001631.  Put another way you have one chance in a little over 600 of bombing every time you start a series.